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95=3x^2+4x+1
We move all terms to the left:
95-(3x^2+4x+1)=0
We get rid of parentheses
-3x^2-4x-1+95=0
We add all the numbers together, and all the variables
-3x^2-4x+94=0
a = -3; b = -4; c = +94;
Δ = b2-4ac
Δ = -42-4·(-3)·94
Δ = 1144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1144}=\sqrt{4*286}=\sqrt{4}*\sqrt{286}=2\sqrt{286}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{286}}{2*-3}=\frac{4-2\sqrt{286}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{286}}{2*-3}=\frac{4+2\sqrt{286}}{-6} $
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